Given A = 2 hat{i} + hat{j},B = 3 hat{j} - ha | vedclass

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(B) Given vectors are $A = 2 \hat{i} + \hat{j}$,$B = 3 \hat{j} - \hat{k}$,and $C = 6 \hat{i} - 2 \hat{k}$.We need to calculate $A - 2B + 3C$.Substitut

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$20 \hat{i} - 5 \hat{j} - 4 \hat{k}$

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(B) Given vectors are $A = 2 \hat{i} + \hat{j}$,$B = 3 \hat{j} - \hat{k}$,and $C = 6 \hat{i} - 2 \hat{k}$.We need to calculate $A - 2B + 3C$.Substitute the given vectors into the expression:$A - 2B + 3C = (2 \hat{i} + \hat{j}) - 2(3 \hat{j} - \hat{k}) + 3(6 \hat{i} - 2 \hat{k})$Expand the terms:$= 2 \hat{i} + \hat{j} - 6 \hat{j} + 2 \hat{k} + 18 \hat{i} - 6 \hat{k}$Group the components of $\hat{i}$,$\hat{j}$,and $\hat{k}$:$= (2 + 18) \hat{i} + (1 - 6) \hat{j} + (2 - 6) \hat{k}$$= 20 \hat{i} - 5 \hat{j} - 4 \hat{k}$

Given $A = 2 \hat{i} + \hat{j}$,$B = 3 \hat{j} - \hat{k}$,and $C = 6 \hat{i} - 2 \hat{k}$. The value of $A - 2B + 3C$ is:

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