$A =2 \hat{ i }+\hat{ j }, B =3 \hat{ j }-\hat{ k }$ and $C =6 \hat{ i }-2 \hat{ k }$ Value of $A -2 B +3 C$ would be
$20 \hat{ i }+5 \hat{ j }+4 \hat{ k }$
$20 \hat{ i }-5 \hat{ j }-4 \hat{ k }$
$4 \hat{ i }+5 \hat{ i }+20 \hat{ k }$
$5 \hat{ i }+4 \hat{ j }+10 \hat{ k }$
A force of $5 N$ acts on a particle along a direction making an angle of $60^{\circ}$ with vertical. Its vertical component will be $.........\,N$
The vector sum of two forces is perpendicular to their vector differences. In that case, the force