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(C) At $STP$,$1 \ mole$ of any ideal gas occupies $22.4 \ L$ of volume.Given that $5.8 \ L$ of the gas has a mass of $7.5 \ g$.Therefore,the mass of $

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$CO$

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(C) At $STP$,$1 \ mole$ of any ideal gas occupies $22.4 \ L$ of volume.Given that $5.8 \ L$ of the gas has a mass of $7.5 \ g$.Therefore,the mass of $22.4 \ L$ (molar mass) of the gas is calculated as:$	ext{Molar mass} = \frac{7.5 \ g}{5.8 \ L} 	imes 22.4 \ L/mol \approx 28.96 \ g/mol \approx 29 \ g/mol$.The molar masses of the given options are:$NO = 14 + 16 = 30 \ g/mol$$N_2O = 28 + 16 = 44 \ g/mol$$CO = 12 + 16 = 28 \ g/mol$$CO_2 = 12 + 32 = 44 \ g/mol$The calculated molar mass of $29 \ g/mol$ is closest to $CO$ $(28 \ g/mol)$.

$7.5 \ g$ of a gas occupies $5.8 \ L$ of volume at $STP$. The gas is

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