$A^{2+}_{(aq.)} + 2e^- \to A_{(s)}$ ; $E^{\circ} = 0.8 \ V$
$B^{3+}_{(aq.)} + 3e^- \to B_{(s)}$ ; $E^{\circ} = 0.6 \ V$
Using the above information,find the ion which will be deposited first at the cathode if a solution containing $A^{2+}_{(aq.)}$ and $B^{3+}_{(aq.)}$ is electrolysed.

  • A
    $A^{2+}_{(aq.)}$
  • B
    $B^{3+}_{(aq.)}$
  • C
    $H^{+}_{(aq.)}$
  • D
    $OH^{-}_{(aq.)}$

Explore More

Similar Questions

The electrochemical cell is set up as follows: $Pt (H_2, 1 \, atm) | HCl (0.1 \, M) || \text{Acetic Acid} (0.1 \, M) | (H_2, 1 \, atm) Pt$. The $E.M.F.$ of the cell is not zero because:

Efficiency of a cell with cell reaction under standard conditions,$A_{(s)} + B^{+} \to A^{+} + B_{(s)}$; $\Delta H^o = -300 \ kJ$ is $70\%$. The standard electrode potential of the cell is :- .................... $V$

An electrochemical cell is set up as follows: $Pt(H_2, 1 \, atm) | 0.1 \, M \, HCl || 0.1 \, M \, CH_3COOH | (H_2, 1 \, atm) Pt$. The $E.M.F.$ of this cell will not be zero because:

Copper displaces which of the following metals from their salt solutions?

The equilibrium constant for the reaction $Zn_{(s)} + Sn^{2+}_{(aq)} \rightleftharpoons Zn^{2+}_{(aq)} + Sn_{(s)}$ is $1 \times 10^{20}$ at $298 \ K$. The magnitude of standard electrode potential of $Sn/Sn^{2+}$ if $E_{Zn^{2+}/Zn}^0 = -0.76 \ V$ is $............ \times 10^{-2} \ V$. (Nearest integer)
Given : $\frac{2.303 \ RT}{F} = 0.059 \ V$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo