$0.01 \ M \ HA(aq.)$ is $2 \%$ ionized,$[OH^{-}]$ of solution is :-
- A$2 \times 10^{-4}$
- B$10^{-8}$
- C$5 \times 10^{-11}$
- D$5 \times 10^{-12}$
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