If two individuals with AB blood group marry | vedclass

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Question

(A) The $ABO$ blood grouping in humans is controlled by the gene $I$. The gene $I$ has three alleles $I^A$,$I^B$,and $i$. When $I^A$ and $I^B$ are pre

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Codominance

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(A) The $ABO$ blood grouping in humans is controlled by the gene $I$. The gene $I$ has three alleles $I^A$,$I^B$,and $i$. When $I^A$ and $I^B$ are present together,they both express their own types of sugars (antigens) because of codominance. In the given cross,both parents have $AB$ blood group (genotype $I^A I^B$). The cross $I^A I^B 	imes I^A I^B$ results in offspring with genotypes $I^A I^A$ ($A$ blood group),$I^A I^B$ ($AB$ blood group),and $I^B I^B$ ($B$ blood group) in the ratio $1:2:1$. Since both alleles $I^A$ and $I^B$ are expressed equally in the $AB$ phenotype,this is an example of codominance.

If two individuals with $AB$ blood group marry and have a large number of children,the children show $A$,$AB$,and $B$ blood groups in a ratio of $1:2:1$. Since proteins of both $A$ and $B$ types are present in individuals with $AB$ blood group,this is an example of:

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