A woman is a carrier for hemophilia (having o | vedclass

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(C) Let $X^H$ be the gene for normal blood clotting and $X^h$ be the gene for hemophilia. Let $X^C$ be the gene for normal vision and $X^c$ be the gen

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$50\%$ hemophilic,color-blind sons and $50\%$ hemophilic sons.

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(C) Let $X^H$ be the gene for normal blood clotting and $X^h$ be the gene for hemophilia. Let $X^C$ be the gene for normal vision and $X^c$ be the gene for color blindness. The woman is a carrier for hemophilia $(X^H X^h)$ and also carries the color blindness gene on one $X$ chromosome. Assuming the genes are linked,her genotype is $X^{Hc} X^h$ (where $c$ is the color blindness allele). The normal man has the genotype $X^{HC} Y$. When they cross: $1$. $X^{Hc} X^h 	imes X^{HC} Y$ $2$. Offspring genotypes: $X^{Hc} X^{HC}$ (Carrier daughter),$X^{Hc} Y$ (Hemophilic and color-blind son),$X^h X^{HC}$ (Carrier daughter),$X^h Y$ (Hemophilic son). Thus,the sons will be $50\%$ hemophilic and color-blind,and $50\%$ hemophilic.

$A$ woman is a carrier for hemophilia (having one gene on each $X$ chromosome) and also carries one gene for color blindness on one $X$ chromosome. She marries a normal man. What will be the phenotype of their offspring?

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