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(B) $1$. The reaction of $1,3-	ext{cyclohexadiene}$ with $NBS$ ($N$-Bromosuccinimide) is an allylic bromination. It introduces a bromine atom at the

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Benzene

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(B) $1$. The reaction of $1,3-	ext{cyclohexadiene}$ with $NBS$ ($N$-Bromosuccinimide) is an allylic bromination. It introduces a bromine atom at the allylic position,forming $3-	ext{bromocyclohexene}$ (Compound $A$).$2$. The reaction of $3-	ext{bromocyclohexene}$ with aqueous $NaOH$ is a nucleophilic substitution reaction ($S_N2$ or $S_N1$),where the $-Br$ group is replaced by an $-OH$ group,forming $3-	ext{cyclohexenol}$ (Compound $B$).$3$. The reaction of $3-	ext{cyclohexenol}$ with concentrated $H_2SO_4$ at high temperature $(\Delta)$ is an acid-catalyzed dehydration reaction. This removes the $-OH$ group and a hydrogen atom from the adjacent carbon to form a double bond,resulting in the formation of $1,3-	ext{cyclohexadiene}$ (which is the starting material) or,through rearrangement/conjugation,it can lead to the formation of benzene if conditions allow for further dehydrogenation. However,in standard textbook problems of this type,the dehydration of $3-	ext{cyclohexenol}$ typically yields $1,3-	ext{cyclohexadiene}$. Looking at the options provided,the most stable aromatic product that can be formed via further elimination/dehydrogenation is benzene. Given the options,$B$ (Benzene) is the intended product.

Identify the final product $C$ in the following reaction sequence:
$1,3-\text{cyclohexadiene}$ $\xrightarrow{NBS} A$ $\xrightarrow{Aq. NaOH} B$ $\xrightarrow{Con. H_2SO_4, \Delta} C$

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Identify the final product $C$ in the following reaction sequence:$1,3-\text{cyclohexadiene}$ $\xrightarrow{NBS} A$ $\xrightarrow{Aq. NaOH} B$ $\xrightarrow{Con. H_2SO_4, \Delta} C$