How many grams of NaOH are required to neutra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The neutralization reaction is: $C_6H_5COOH + NaOH 	o C_6H_5COONa + H_2O$. The molar mass of benzoic acid $(C_6H_5COOH)$ is $122 \ g/mol$. The mo

Vedclass · Accepted Answer

$4.0$

Vedclass · Answer

(B) The neutralization reaction is: $C_6H_5COOH + NaOH 	o C_6H_5COONa + H_2O$. The molar mass of benzoic acid $(C_6H_5COOH)$ is $122 \ g/mol$. The molar mass of $NaOH$ is $40 \ g/mol$. Since the stoichiometry is $1:1$,the moles of $NaOH$ required equal the moles of benzoic acid. Moles of benzoic acid = $\frac{12.2 \ g}{122 \ g/mol} = 0.1 \ mol$. Moles of $NaOH$ required = $0.1 \ mol$. Mass of $NaOH$ = $0.1 \ mol 	imes 40 \ g/mol = 4.0 \ g$.

How many grams of $NaOH$ are required to neutralize $12.2 \ g$ of benzoic acid (in $g$)?

Similar Questions

The volume of gas at $NTP$ produced by $100 \ g$ of $CaC_2$ with water is $:- CaC_2 + 2 H_2O \rightarrow Ca(OH)_2 + C_2H_{2(g)}$ (in $L$)

When a hydrated salt,$Na_2SO_4 \cdot nH_2O$,is heated,it loses $56\%$ of its weight and becomes anhydrous. What is the approximate value of $n$?

How many litres of oxygen (at $STP$) are required for complete combustion of $39 \ g$ of liquid benzene?
(Atomic weights: $C=12, O=16, H=1$)

What is the volume occupied by $2.5 \ mol$ of ammonia gas at $\text{STP}$ (in $dm^3$)?

$23 \ g$ of $Na$ metal reacts with ethanol to produce which of the following?

Vedclass Test Series

Exam Paper Generator

Online Exam Module