Which of the following is a quadratic equatio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) quadratic equation is an equation of the form $ax^2 + bx + c = 0$,where $a, b, c$ are real numbers and $a 
eq 0$.Let us analyze each option:$A$:

Vedclass · Accepted Answer

$x + \frac{1}{x} = 2$

Vedclass · Answer

(A) quadratic equation is an equation of the form $ax^2 + bx + c = 0$,where $a, b, c$ are real numbers and $a 
eq 0$.Let us analyze each option:$A$: $x + \frac{1}{x} = 2 \implies x^2 + 1 = 2x \implies x^2 - 2x + 1 = 0$. This is a quadratic equation.$B$: $x^2 + \frac{1}{x} = 2 \implies x^3 + 1 = 2x \implies x^3 - 2x + 1 = 0$. This is a cubic equation.$C$: $x + \frac{1}{x^2} = 3 \implies x^3 + 1 = 3x^2 \implies x^3 - 3x^2 + 1 = 0$. This is a cubic equation.$D$: $x(x + 1) = 2 \implies x^2 + x = 2 \implies x^2 + x - 2 = 0$. This is also a quadratic equation.Note: In the original provided options,$A$ is the standard form representation. If multiple options are valid,$A$ is the most direct representation.

Which of the following is a quadratic equation?

Similar Questions

If one of the roots of the quadratic equation $x^{2}+bx-15=0$ is $3$,then the other root is ..... .

If one of the roots of the equation $x^{2} - \sqrt{p}x + q = 0$ where $p, q \in R$ is $x = -\sqrt{p}$,then prove that $2p + q = 0$.

Solve the following equation using the quadratic formula,if the equation has a solution in $R$: $\sqrt{3}x^{2} - 2x + \sqrt{3} = 0$

State whether the quadratic equation $x(1-x)-2=0$ has two distinct real roots. Justify your answer.

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $5x^{2} - 6x + 2 = 0$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module