The compound X is formed by the decarboxylati | vedclass

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(C) The reaction shown is the decarboxylation of acetoacetic acid $(CH_3COCH_2COOH \xrightarrow{\Delta} CH_3COCH_3 + CO_2)$.Thus,$X$ is acetone $(CH_3

Vedclass · Accepted Answer

$CH_3-C \equiv CH \xrightarrow[H_2O]{Hg^{+2}}$

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(C) The reaction shown is the decarboxylation of acetoacetic acid $(CH_3COCH_2COOH \xrightarrow{\Delta} CH_3COCH_3 + CO_2)$.Thus,$X$ is acetone $(CH_3COCH_3)$.Now,let us evaluate the options:Option $A$: $CH_3-CH_2-CH_2-Cl \xrightarrow{LiAlH_4} CH_3-CH_2-CH_3$ (Propane).Option $B$: $CH_3-CH_2-COOH \xrightarrow{P + HI} CH_3-CH_2-CH_3$ (Propane).Option $C$: $CH_3-C \equiv CH \xrightarrow[H_2O]{Hg^{+2}} CH_3-CO-CH_3$ (Acetone).Since $X$ is acetone,option $C$ is the correct method to form $X$.

The compound $X$ is formed by the decarboxylation of acetoacetic acid $(CH_3COCH_2COOH)$ upon heating. $X$ can also be formed by:

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