Which of the following optioms correctly represents relationship between $t_{7/8}$ and $t_{1/2}$ where $t_{7/8}$ represent time required for concentration to become $\frac{1}{8} \,th$ of original for  a reaction of order $'n'$

  • A

    $t_{7/8} =(2n+ 1)\ t_{1/2}$

  • B

    $t_{7/8} = t_{1/2}\, [2^{n-1} - 1]$

  • C

    $t_{7/8} = t_{1/2}\, [2^{n-1} + 1]$

  • D

    $t_{7/8} = t_{1/2}\, [2^{2n-2} + 1+2^{n-1}]$

Similar Questions

For a chemical reaction $A \to B$ it is found that the rate of reaction doubles, when the concentration of $A$ is increased four times. The order in $A$  for this reaction is

  • [AIIMS 1997]

For any reaction, if we plot a graph between time '$t$' and $\log (a - x)$, a simple line is obtained. The order of reaction is

Reaction $2A + B \to$  product,  rate law is $\frac{{ - d[A]}}{{dt}}\, = \,K[A].$ At a time when $t\, = \,\frac{{{t_{1/2}}}}{{\ln\,2}},$ concentration of the reactant is

For a particular reaction, the rate expression is given as $r = k[A] [B]^{0.5}$. If the volume of vessel is reduced to one-fourth of the initial volume, the rate of reaction would

Explain order of reaction of complex reaction by giving examples.