The ionisation enthalpies of elements of the second period are given below: Ionisation enthalpy / $kcal \, mol^{-1}$: $520, 899, 801, 1086, 1402, 1314, 1681, 2080$. Match the correct enthalpy with the elements and complete the graph given in Fig. Also,write the symbols of the elements with their atomic numbers.

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(N/A) The elements of the second period ($Z=3$ to $10$) and their corresponding first ionisation enthalpies $(IE_1)$ in $kcal \, mol^{-1}$ are as follows:
$1$. $Li$ $(Z=3)$: $520$
$2$. $Be$ $(Z=4)$: $899$
$3$. $B$ $(Z=5)$: $801$
$4$. $C$ $(Z=6)$: $1086$
$5$. $N$ $(Z=7)$: $1402$
$6$. $O$ $(Z=8)$: $1314$
$7$. $F$ $(Z=9)$: $1681$
$8$. $Ne$ $(Z=10)$: $2080$
General Trend: As we move from left to right across a period,the atomic radius decreases and the effective nuclear charge increases,leading to a general increase in ionisation enthalpy.
Exceptions:
- $Be$ $(2s^2)$ has a higher $IE_1$ than $B$ $(2s^2 2p^1)$ because the $2s$ orbital is fully filled and more stable.
- $N$ $(2s^2 2p^3)$ has a higher $IE_1$ than $O$ $(2s^2 2p^4)$ because the $2p$ subshell is half-filled,providing extra stability.

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Given below are two statements:
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Statement-$II$: $S > Se > Te > Po > O$ is the correct order in terms of the magnitude of electron gain enthalpy values.
In the light of the above statements,choose the correct answer from the options given below:

Which of the following statement$(s)$ is/are correct?

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Which one of the following sets of ions represents a collection of isoelectronic species?

Which of the following orders is $NOT$ correct with respect to the mentioned properties?

The set of elements that differ in mutual relationship from those of the other sets is:

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