Ph-C(ClF_2)=C(F)_2 xrightarrow{1,eq. , ^-OEt} | vedclass

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(A) The reaction is a nucleophilic vinylic substitution $(S_N V)$.In $Ph-C(ClF_2)=C(F)_2$,the $C(F)_2$ carbon is highly electrophilic due to the stron

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(A) The reaction is a nucleophilic vinylic substitution $(S_N V)$.In $Ph-C(ClF_2)=C(F)_2$,the $C(F)_2$ carbon is highly electrophilic due to the strong inductive effect of the two fluorine atoms.The ethoxide ion $(^-OEt)$ attacks the $C(F)_2$ carbon to form a carbanion intermediate,which is stabilized by the $Ph$ group and the $ClF_2C$ group through resonance and inductive effects.Subsequently,a fluoride ion $(F^-)$ is eliminated to restore the double bond.Since the nucleophile attacks the terminal $CF_2$ group,the product is $Ph-C(ClF_2)=C(F)(OEt)$.Comparing the stereochemistry,the major product is the one where the bulky $Ph$ and $ClF_2C$ groups are trans to each other to minimize steric hindrance.

$Ph-C(ClF_2)=C(F)_2 \xrightarrow{1\,eq. \, ^-OEt} A$ (major product),$A$ is

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