(CH_3)_2C=C(CH_3)_2 xrightarrow{text{Catalyst | vedclass

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(C) The reaction is the catalytic hydrogenation of $2,3-	ext{dimethylbut-2-ene}$.$(CH_3)_2C=C(CH_3)_2 + H_2 \xrightarrow{	ext{Catalyst}} (CH_3)_2CH-

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(C) The reaction is the catalytic hydrogenation of $2,3-	ext{dimethylbut-2-ene}$.$(CH_3)_2C=C(CH_3)_2 + H_2 \xrightarrow{	ext{Catalyst}} (CH_3)_2CH-CH(CH_3)_2$.The product formed is $2,3-	ext{dimethylbutane}$.In $2,3-	ext{dimethylbutane}$,there are no chiral carbon atoms present because the molecule is symmetric and each carbon atom is bonded to at least two identical groups.Since there are no chiral centers,the molecule is achiral and exhibits $0$ optical isomers.

$(CH_3)_2C=C(CH_3)_2 \xrightarrow{\text{Catalyst}, H_2} \text{Number of optical isomers in the product?}$

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