Alkanes are generally resistant to oxidation under mild conditions. What is your opinion regarding the following reaction?
$C_4H_{10(g)} + \frac{13}{2}O_{2(g)} \to 4CO_{2(g)} + 5H_2O_{(l)}$
$C_4H_{10(g)} + \frac{13}{2}O_{2(g)} \to 4CO_{2(g)} + 5H_2O_{(l)}$
(A) The given reaction represents the combustion of butane $(C_4H_{10})$.
Combustion is a highly exothermic oxidation reaction.
In the reactant $C_4H_{10}$,the oxidation state of carbon is $-2.5$ (average). In the product $CO_2$,the oxidation state of carbon is $+4$.
Since the oxidation number of carbon increases from $-2.5$ to $+4$,this process is an oxidation reaction.
Therefore,the combustion of all alkanes is fundamentally an oxidation reaction.
Combustion is a highly exothermic oxidation reaction.
In the reactant $C_4H_{10}$,the oxidation state of carbon is $-2.5$ (average). In the product $CO_2$,the oxidation state of carbon is $+4$.
Since the oxidation number of carbon increases from $-2.5$ to $+4$,this process is an oxidation reaction.
Therefore,the combustion of all alkanes is fundamentally an oxidation reaction.
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