State Gay-Lussac's Law.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Gay-Lussac's Law states that for a given mass of an ideal gas, the pressure $(P)$ of the gas is directly proportional to its absolute temperature $(T)$, provided the volume $(V)$ remains constant.
Mathematically, this is expressed as:
$P \propto T$ (at constant $V$ and mass)
$P = kT$ or $\frac{P}{T} = \text{constant}$
where $P$ is the pressure, $T$ is the absolute temperature in Kelvin, and $k$ is a proportionality constant.

Explore More

Similar Questions

$A$ box contains $n$ molecules of a gas. How will the pressure of the gas be affected if the number of molecules is made $2n$?

What is an ideal gas? Write the state equation for an ideal gas. Write and explain the different laws relating to gases.

Difficult
View Solution

An ideal gas at atmospheric pressure has a temperature of $300 \,K$ and a volume of $1 \,m^3$. If its temperature and volume are both doubled,its pressure will be ...........

The pressure versus temperature graph of an ideal gas is as shown in the figure. The density of the gas at point $A$ is ${\rho _0}$. The density at point $B$ will be

The volume of a gas at $21^{\circ}C$ temperature and $768 \,mm$ pressure is $1 \,L$. If the density of the gas is $1.2 \,g/L$ at $NTP$,then its mass will be ..... $g$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo