Which set of quantum numbers is not possible | vedclass

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(B) The electronic configuration of $Al$ $(Z = 13)$ is $1s^2 2s^2 2p^6 3s^2 3p^1$.The last electron enters the $3p$ orbital.For the $3p$ orbital,the q

Vedclass · Accepted Answer

$3, 0, 0, +\frac{1}{2}$

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(B) The electronic configuration of $Al$ $(Z = 13)$ is $1s^2 2s^2 2p^6 3s^2 3p^1$.The last electron enters the $3p$ orbital.For the $3p$ orbital,the quantum numbers are:Principal quantum number $(n)$ = $3$.Azimuthal quantum number $(l)$ = $1$.Magnetic quantum number $(m)$ can be $-1, 0, +1$.Spin quantum number $(s)$ can be $+\frac{1}{2}$ or $-\frac{1}{2}$.Option $B$ represents the quantum numbers for an electron in the $3s$ orbital $(n=3, l=0, m=0, s=+\frac{1}{2})$,which is not the last electron of $Al$. Therefore,this set is not possible for the last electron.

Which set of quantum numbers is not possible for the last electron of $Al$ $(Z = 13)$:- value of $n, l, m, s$ respectively?

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