Which of the following pairs of complexes are | vedclass

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(D) Molar conductivity depends on the number of ions produced in an aqueous solution.For $[CoBr(NH_3)_5]SO_4$,the dissociation is $[CoBr(NH_3)_5]SO_4

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$[CoBr(NH_3)_5]SO_4$ and $[Co(SO_4)(NH_3)_5]Br$

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(D) Molar conductivity depends on the number of ions produced in an aqueous solution.For $[CoBr(NH_3)_5]SO_4$,the dissociation is $[CoBr(NH_3)_5]SO_4 \rightarrow [CoBr(NH_3)_5]^{2+} + SO_4^{2-}$,which gives $2$ ions.For $[Co(SO_4)(NH_3)_5]Br$,the dissociation is $[Co(SO_4)(NH_3)_5]Br \rightarrow [Co(SO_4)(NH_3)_5]^+ + Br^-$,which gives $2$ ions.Wait,let us re-evaluate the options.Option $D$ involves ionization isomers where the ions produced are different ($SO_4^{2-}$ vs $Br^-$).Although both produce $2$ ions,the charge density and mobility of $SO_4^{2-}$ and $Br^-$ differ,leading to different molar conductivities.Therefore,the pair $[CoBr(NH_3)_5]SO_4$ and $[Co(SO_4)(NH_3)_5]Br$ are ionization isomers with different molar conductivities.

List-$I$ (Complexes)	List-$II$ (Types)
$a$. $[Co(NH_3)_5NO_2]Cl_2$ and $[Co(NH_3)_5ONO]Cl_2$	$i$. Linkage isomerism
$b$. $[Cr(NH_3)_6][Co(CN)_6]$ and $[Cr(CN)_6][Co(NH_3)_6]$	$ii$. Coordination isomerism
$c$. $[Co(NH_3)_5(SO_4)]Br$ and $[Co(NH_3)_5Br]SO_4$	$iii$. Ionisation isomerism
$d$. $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$	$iv$. Solvate isomerism

Which of the following pairs of complexes are isomeric with each other but their aqueous solutions exhibit different molar conductivities?

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