Which of the following is the correct structu | vedclass

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(A) -glucose is the naturally occurring isomer where the $-OH$ group on the chiral carbon furthest from the aldehyde group (i.e.,$C-5$) is on the righ

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(A) -glucose is the naturally occurring isomer where the $-OH$ group on the chiral carbon furthest from the aldehyde group (i.e.,$C-5$) is on the right side in the Fischer projection.$L$-glucose is the enantiomer of $D$-glucose.To obtain the structure of $L$-glucose,we must invert the configuration at every chiral center $(C-2, C-3, C-4, C-5)$ of $D$-glucose.In $D$-glucose,the $-OH$ groups are at: $C-2$ (right),$C-3$ (left),$C-4$ (right),$C-5$ (right).Therefore,in $L$-glucose,the $-OH$ groups must be at: $C-2$ (left),$C-3$ (right),$C-4$ (left),$C-5$ (left).This corresponds to the structure where the $-OH$ group on $C-5$ is on the left,which is the definition of the $L$-configuration.

Which of the following is the correct structure of $L$-glucose?

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