Which of the following has a square planar ge | vedclass

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(A) In $[PtCl_4]^{2-}$,the central metal ion is $Pt^{2 }$ ($5d^8$ configuration).$Pt$ is a $5d$ series element,and for $5d$ elements,the crystal field

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$[PtCl_4]^{2-}$

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(A) In $[PtCl_4]^{2-}$,the central metal ion is $Pt^{2 }$ ($5d^8$ configuration).$Pt$ is a $5d$ series element,and for $5d$ elements,the crystal field splitting energy $(\Delta_o)$ is very high,even with weak ligands like $Cl^-$.This high splitting energy forces the pairing of electrons in the $5d$ orbitals,resulting in $dsp^2$ hybridization.Therefore,$[PtCl_4]^{2-}$ exhibits a square planar geometry.In contrast,$[NiCl_4]^{2-}$,$[CoCl_4]^{2-}$,and $[FeCl_4]^{2-}$ involve $3d$ metals with weak ligands,leading to $sp^3$ hybridization and tetrahedral geometry.

Which of the following has a square planar geometry?
(At. nos.: $Fe=26, Co=27, Ni=28, Pt=78$)

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Which of the following has a square planar geometry?(At. nos.: $Fe=26, Co=27, Ni=28, Pt=78$)