Which of the following has ppi-dpi bonding? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In $SO_3^{2-}$,the central sulfur atom has an expanded octet and utilizes its vacant $d$-orbitals to form $\pi$-bonds with oxygen atoms.Specifical

Vedclass · Accepted Answer

$SO_3^{2-}$

Vedclass · Answer

(B) In $SO_3^{2-}$,the central sulfur atom has an expanded octet and utilizes its vacant $d$-orbitals to form $\pi$-bonds with oxygen atoms.Specifically,the lone pair on the oxygen atom is donated into the vacant $d$-orbital of the sulfur atom,resulting in $p\pi-d\pi$ bonding.In contrast,$NO_3^-$,$BO_3^{3-}$,and $CO_3^{2-}$ involve elements from the second period ($N$,$B$,$C$),which lack $d$-orbitals,and thus only exhibit $p\pi-p\pi$ bonding.Therefore,the correct option is $B$.

Which of the following has $p\pi-d\pi$ bonding?

Similar Questions

Identify the molecule containing a triple bond.

Define the bond length.

The skeletal structure of $CH_{3}COOH$ as shown below is incorrect because some of the bonds are represented wrongly. Write the correct Lewis structure for acetic acid.

The number of electrons involved in the bond formation of $N_2$ molecule is:

Bond dissociation energies of $HF, HCl, HBr$ follow the order:

Vedclass Test Series

Exam Paper Generator

Online Exam Module