Which of the following compounds will behave | vedclass

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(C) reducing sugar must have a free hemiacetal or hemiketal group,which can exist in equilibrium with an open-chain aldehyde or ketone form. In an aqu

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(C) reducing sugar must have a free hemiacetal or hemiketal group,which can exist in equilibrium with an open-chain aldehyde or ketone form. In an aqueous $KOH$ solution,an ester group (like $-OCOCH_3$) can undergo hydrolysis to form a free hydroxyl group $(-OH)$. Option $C$ contains an ester group $(-OCOCH_3)$ at the anomeric carbon. In the presence of $aq. KOH$,this ester undergoes base-catalyzed hydrolysis to yield a free hemiacetal group ($-OH$ at the anomeric carbon). This free hemiacetal group can then open up to form an aldehyde,which acts as a reducing agent. Therefore,the compound in option $C$ will behave as a reducing sugar in $aq. KOH$ solution.

Which of the following compounds will behave as a reducing sugar in $aq. KOH$ solution?

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