Which of the following compounds is optically | vedclass

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(A) compound is optically active if it lacks a plane of symmetry and contains at least one chiral carbon atom (a carbon atom bonded to four different

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$CH_3-CH(OH)-COOH$

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(A) compound is optically active if it lacks a plane of symmetry and contains at least one chiral carbon atom (a carbon atom bonded to four different groups). $A$. $CH_3-CH(OH)-COOH$ (Lactic acid) has a chiral carbon atom bonded to $-H$,$-OH$,$-CH_3$,and $-COOH$. It is optically active. $B$. The structure is $2,3$-butanediol. The meso form has a plane of symmetry and is optically inactive. $C$. The structure is $1,2$-dichlorocyclobutane. The cis-isomer has a plane of symmetry and is optically inactive. $D$. $CH_3-CH=CH-CH_3$ (But-$2$-ene) is a planar molecule and does not contain a chiral carbon atom; it is optically inactive. Therefore,the correct answer is $A$.

Which of the following compounds is optically active?

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