Which line has the maximum wavelength and fre | vedclass

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(A-B) The wavelength $\lambda$ is related to the energy difference $\Delta E$ by the formula $\Delta E = \frac{hc}{\lambda}$.For a spectral series,the

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(A-B) The wavelength $\lambda$ is related to the energy difference $\Delta E$ by the formula $\Delta E = \frac{hc}{\lambda}$.For a spectral series,the energy difference is given by $\Delta E = 13.6 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} ight) 	ext{ eV}$.$1$. Maximum Wavelength: To have the maximum wavelength,the energy difference $\Delta E$ must be minimum. This occurs for the transition between the closest energy levels,i.e.,from $n_2 = n_1 + 1$ to $n_1$ (the first line of the series).$2$. Maximum Frequency: Since frequency $
u = \frac{\Delta E}{h}$,the maximum frequency corresponds to the maximum energy difference. This occurs for the transition from $n_2 = \infty$ to $n_1$ (the series limit or the last line of the series).

Which line has the maximum wavelength and frequency in each series of the hydrogen spectrum?

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