When a wave travels in a medium, the particle | vedclass

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Question

For the wave $A \sin (\omega t-k x),$ wave velocity is $\frac{\omega}{k}$ and maximum particle velocity is $\omega A$

Therefore:

For the given w

Vedclass · Accepted Answer

$c = \frac{1}{\pi a}$

Vedclass · Answer

For the wave $A \sin (\omega t-k x),$ wave velocity is $\frac{\omega}{k}$ and maximum particle velocity is $\omega A$

Therefore:

For the given wave, the wave speed is given by, $v_{w}=\frac{b}{c}$

And the maximum particle speed is given by: $v_{p}=2 \pi a b$ So, $v_{p}=2 v_{w}$

$\Rightarrow c=\frac{1}{\pi a}$

When a wave travels in a medium, the particle displacement is given by : $y = asin\, 2 \pi \,(bt -cx)$, where $a, b$ and $c$ are constants. The maximum particle velocity will be twice the wave velocity if

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