When left( frac{m}{x} right) is plotted again | vedclass

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(C) Given the Langmuir adsorption isotherm equation: $\frac{x}{m} = \frac{ap}{1 + bp}$.Taking the reciprocal of both sides,we get: $\frac{m}{x} = \fra

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$\frac{1}{a}, \frac{b}{a}$

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(C) Given the Langmuir adsorption isotherm equation: $\frac{x}{m} = \frac{ap}{1 + bp}$.Taking the reciprocal of both sides,we get: $\frac{m}{x} = \frac{1 + bp}{ap}$.This can be rewritten as: $\frac{m}{x} = \frac{1}{ap} + \frac{bp}{ap} = \left( \frac{1}{a} \right) \left( \frac{1}{p} \right) + \frac{b}{a}$.Comparing this with the equation of a straight line $y = mx + c$,where $y = \frac{m}{x}$ and $x = \frac{1}{p}$:The slope $(m)$ is $\frac{1}{a}$ and the intercept $(c)$ is $\frac{b}{a}$.

When $\left( \frac{m}{x} \right)$ is plotted against $\frac{1}{p}$ for the equation $\frac{x}{m} = \frac{ap}{1 + bp}$,we get a straight line. What are the slope and intercept of this line?

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