What product would you expect to obtain from | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Dimethyl carbonate $(CH_3OCOOCH_3)$ reacts with an excess of phenylmagnesium bromide $(PhMgBr)$ to produce triphenylmethanol $(Ph_3COH)$. The reac

Vedclass · Accepted Answer

$Ph_3C-OH$

Vedclass · Answer

(C) Dimethyl carbonate $(CH_3OCOOCH_3)$ reacts with an excess of phenylmagnesium bromide $(PhMgBr)$ to produce triphenylmethanol $(Ph_3COH)$. The reaction occurs in three steps:$1.$ Nucleophilic acyl substitution of the first methoxy group to form methyl benzoate: $CH_3OCOOCH_3 + PhMgBr \rightarrow PhCOOCH_3 + CH_3OMgBr$$2.$ Nucleophilic acyl substitution of the second methoxy group to form benzophenone: $PhCOOCH_3 + PhMgBr \rightarrow PhCOPh + CH_3OMgBr$$3.$ Nucleophilic addition to the ketone followed by hydrolysis to form triphenylmethanol: $PhCOPh + PhMgBr$ $\rightarrow Ph_3COMgBr$ $\xrightarrow{H_3O^{+}} Ph_3COH$.

What product would you expect to obtain from a Grignard reaction when an excess of phenylmagnesium bromide reacts with dimethyl carbonate $CH_3OCOOCH_3$?

Similar Questions

$C_{4}H_{10}O$ $\xrightarrow{K_{2}Cr_{2}O_{7} / H_{2}SO_{4}} C_{4}H_{8}O$ $\xrightarrow{I_{2} / NaOH, \text{Warm}} CHI_{3}$
Here,$N$ is

In the given pairs of alcohols,in which pair is the second alcohol more reactive than the first towards hydrogen bromide $(HBr)$?

When concentrated $H_2SO_4$ reacts with $X$ at a temperature of $160 - 170 \, ^\circ C$,ethylene is obtained. What is $X$?

Which compound is soluble in water?

The reaction of ethylene glycol with $PI_3$ gives:

Vedclass Test Series

Exam Paper Generator

Online Exam Module