What happens to the fringe width in Young's d | vedclass

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(A) The formula for fringe width in Young's double-slit experiment is given by $\beta = \frac{D \lambda}{d}$,where $D$ is the distance between the scr

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shrinks

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(A) The formula for fringe width in Young's double-slit experiment is given by $\beta = \frac{D \lambda}{d}$,where $D$ is the distance between the screen and the slits,$\lambda$ is the wavelength of light,and $d$ is the distance between the slits.When the experiment is performed in a medium like glycerine with refractive index $\mu$,the wavelength of light changes to $\lambda^{\prime} = \frac{\lambda}{\mu}$.Substituting this into the fringe width formula,the new fringe width $\beta^{\prime}$ becomes $\beta^{\prime} = \frac{D \lambda^{\prime}}{d} = \frac{D \lambda}{\mu d} = \frac{\beta}{\mu}$.Since the refractive index of glycerine $\mu > 1$,it follows that $\beta^{\prime} Therefore,the fringe width decreases or shrinks.

What happens to the fringe width in Young's double-slit experiment if it is performed in glycerine instead of air?

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