The wavelengths of light used in an optical i | vedclass

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(D) The resolving power $(RP)$ of an optical instrument, such as a microscope or telescope, is inversely proportional to the wavelength $(\lambda)$ of

Vedclass · Accepted Answer

$5 : 4$

Vedclass · Answer

(D) The resolving power $(RP)$ of an optical instrument, such as a microscope or telescope, is inversely proportional to the wavelength $(\lambda)$ of the light used.Mathematically, $RP \propto \frac{1}{\lambda}$.Given the wavelengths ${\lambda _1 = 4000 \ \mathring{A}}$ and ${\lambda _2 = 5000 \ \mathring{A}}$.The ratio of their resolving powers is $\frac{RP_1}{RP_2} = \frac{\lambda _2}{\lambda _1}$.Substituting the values, we get $\frac{RP_1}{RP_2} = \frac{5000}{4000} = \frac{5}{4}$.Therefore, the ratio of their resolving powers is $5:4$.

The wavelengths of light used in an optical instrument are ${\lambda _1 = 4000 \ \mathring{A}}$ and ${\lambda _2 = 5000 \ \mathring{A}}$. The ratio of their respective resolving powers (corresponding to ${\lambda _1}$ and ${\lambda _2}$) is:

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