True or False: In the reaction $Cr_2O_7^{2-} \xrightarrow{H^{+}} Cr^{3+}$,the equivalent mass of $Cr_2O_7^{2-}$ is $\frac{\text{molecular mass}}{6}$.

(A) True.
In the reaction $Cr_2O_7^{2-} \rightarrow 2Cr^{3+}$,the oxidation state of $Cr$ changes from $+6$ to $+3$.
Total change in oxidation state for two $Cr$ atoms $= 2 \times (6 - 3) = 6$.
Therefore,the n-factor is $6$.
Equivalent mass $= \frac{\text{molecular mass}}{\text{n-factor}} = \frac{\text{molecular mass}}{6}$.