Transition element makes complex compound due to
Transition element makes complex compound due to
- A
Presence of empty $d-$ orbital
- B
large size
- C
Variable valency
- D
presence of $2e^-$
Similar Questions
$\underbrace {\mathop {Hg{I_2}\,}\limits_{'X'} \xrightarrow[{Sublimation}]{\Delta }\,\mathop {Hg{I_2}}\limits_{'Y'} \xrightarrow{{Cooling}}\mathop {Hg{I_2}}\limits_{'Z'} }_{On\,\,rubbing}$
$\underbrace {\mathop {Hg{I_2}\,}\limits_{'X'} \xrightarrow[{Sublimation}]{\Delta }\,\mathop {Hg{I_2}}\limits_{'Y'} \xrightarrow{{Cooling}}\mathop {Hg{I_2}}\limits_{'Z'} }_{On\,\,rubbing}$
Which of the following elements is alloyed with copper to form brass
Which of the following elements is alloyed with copper to form brass
Why do the transition elements exhibit higher enthalpies of atomisation?
Why do the transition elements exhibit higher enthalpies of atomisation?
Which of the following set of elements does not belong to transitional elements set
Which of the following set of elements does not belong to transitional elements set
The "spin-only" magnetic moment [ in units of Bohrmagneton, $(\mu _B )$ ] of $Ni^{2+}$ in aqueous solution would be (At. No. $Ni= 28)$
The "spin-only" magnetic moment [ in units of Bohrmagneton, $(\mu _B )$ ] of $Ni^{2+}$ in aqueous solution would be (At. No. $Ni= 28)$
- [AIEEE 2006]