Three concurrent forces of the same magnitude | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) In $N$ forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given

$	heta = \frac

Vedclass · Accepted Answer

$120^&deg;$ equilateral triangle

Vedclass · Answer

(a) In $N$ forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given

$	heta = \frac{{360}}{N}$$ = \frac{{360}}{3} = 120^\circ $

If these three vectors are represented by three sides of triangle then they form equilateral triangle

Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces Also name the triangle formed by the forces as sides

Similar Questions

If $| A |=2$ and $| B |=4$ and angle between them is $60^{\circ}$, then $| A - B |$ is

Two forces of $10 \,N$ and $6 \,N$ act upon a body. The direction of the forces are unknown. The resultant force on the body may be .........$N$

Let the angle between two nonzero vectors $\overrightarrow A $ and $\overrightarrow B $ be $120^°$ and resultant be $\overrightarrow C $

In the diagram shown in figure

Forces ${F_1}$ and ${F_2}$ act on a point mass in two mutually perpendicular directions. The resultant force on the point mass will be