ત્રણ સિક્કા એક વાર ઉછાળવામાં આવે છે. નીચે આપેલ ઘટનાની સંભાવના શોધો.

વધુમાં વધુ બે કાંટા મળે. 

When three coins are tossed once, the sample space is given by $S =\{ HHH , HHT , HTH , THH , HTT , THT , TTH , TTT \}$

$\therefore$ Accordingly, $n ( S )=8$

It is known that the probability of an event $A$ is given by

$P ( A )=\frac{\text { Number of outcomes favourable to } A }{\text { Total number of possible outcomes }}=\frac{n( A )}{n( S )}$

Let $J$ be the event of the occurrence of at most $2$ tails.

Accordingly, $J=\{H H H,\, H H T , \,H T H ,  \,T H H , \,H T T , \,T H T , \, T T H \} ~$

$\therefore P(J)=\frac{n(J)}{n(S)}=\frac{7}{8}$