(B) The Balmer series corresponds to electronic transitions where the final orbit is ${n_1} = 2$.The lines in the series are defined by the initial or

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(B) The Balmer series corresponds to electronic transitions where the final orbit is ${n_1} = 2$.The lines in the series are defined by the initial orbit ${n_2}$:- First line: ${n_2} = 3 \to {n_1} = 2$- Second line: ${n_2} = 4 \to {n_1} = 2$- Third line: ${n_2} = 5 \to {n_1} = 2$Therefore,the third line corresponds to the transition from $n = 5$ to $n = 2$.

Class 11 Chemistry Structure of Atom Atomic models and Planck's quantum theory

Easy

The third line in the Balmer series corresponds to an electronic transition between which Bohr's orbits in hydrogen?

A
$5 \to 3$
B
$5 \to 2$
C
$4 \to 3$
D
$4 \to 2$

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Structure of Atom

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Atomic models and Planck's quantum theory

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The third line in the Balmer series corresponds to an electronic transition between which Bohr's orbits in hydrogen?

Similar Questions

If $\lambda_0$ and $\lambda$ are the threshold wavelength and the wavelength of incident light,respectively,the velocity of the photoelectron ejected from the metal surface is:

If the wavelength of an electromagnetic radiation is $2000 \ \text{Å}$,what is its energy in ergs?

Thomson's atomic model is also known as .....

What is the hydrogen spectrum? Give its characteristics.

The energy of an electron in the first Bohr orbit of the hydrogen atom is $-13.6 \ eV$. Calculate the energy of an electron in the first Bohr orbit of $He^{+}$ in $eV$.

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