The species with spin only magnetic moment of | vedclass

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Question

(A) The spin only magnetic moment is given by the formula $\mu_{eff} = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.For $\mu_{eff

Vedclass · Accepted Answer

$[CoF_3(H_2O)_3]$

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(A) The spin only magnetic moment is given by the formula $\mu_{eff} = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.For $\mu_{eff} = \sqrt{24} \ BM$,we have $n(n+2) = 24$,which gives $n = 4$.In $[CoF_3(H_2O)_3]$,$Co$ is in the $+3$ oxidation state ($3d^6$ configuration). $F^-$ and $H_2O$ are weak field ligands,so the electrons remain unpaired in the $t_{2g}$ and $e_g$ orbitals,resulting in $4$ unpaired electrons.In $[CoCl_4]^{2-}$,$Co$ is in the $+2$ oxidation state ($3d^7$ configuration),resulting in $3$ unpaired electrons.In $[NiCl_4]^{2-}$,$Ni$ is in the $+2$ oxidation state ($3d^8$ configuration),resulting in $2$ unpaired electrons.In $[Ni(H_2O)_6]^{2+}$,$Ni$ is in the $+2$ oxidation state ($3d^8$ configuration),resulting in $2$ unpaired electrons.Thus,$[CoF_3(H_2O)_3]$ is the correct species.

Components	$\%$ of the total cellular mass
$A$. Water	$1$. $70-90$
$B$. Protein	$2$. $10-15$
$C$. Carbohydrates	$3$. $3$
$D$. Lipids	$4$. $2$
$E$. Nucleic acids	$5$. $5-7$
$F$. Ions	$6$. $1$

The species with spin only magnetic moment of $\sqrt{24} \ BM$ is

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Components $\%$ of the total cellular mass

$A$. Water $1$. $70-90$

$B$. Protein $2$. $10-15$

$C$. Carbohydrates $3$. $3$

$D$. Lipids $4$. $2$

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