The solubility products (K_{sp}) of three spa | vedclass

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(C) For a salt of type $M_2X$,the solubility product is $K_{sp} = (2s)^2(s) = 4s^3$,so $s = (K_{sp}/4)^{1/3}$.For a salt of type $MX$,the solubility p

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$MX > M_2X > MX_3$

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(C) For a salt of type $M_2X$,the solubility product is $K_{sp} = (2s)^2(s) = 4s^3$,so $s = (K_{sp}/4)^{1/3}$.For a salt of type $MX$,the solubility product is $K_{sp} = (s)(s) = s^2$,so $s = (K_{sp})^{1/2}$.For a salt of type $MX_3$,the solubility product is $K_{sp} = (s)(3s)^3 = 27s^4$,so $s = (K_{sp}/27)^{1/4}$.Assuming $K_{sp} = 1$ for comparison:For $M_2X$,$s = (1/4)^{1/3} \approx 0.63$.For $MX$,$s = (1)^{1/2} = 1.0$.For $MX_3$,$s = (1/27)^{1/4} \approx 0.44$.Comparing the values,the order of solubility is $MX > M_2X > MX_3$.

The solubility products $(K_{sp})$ of three sparingly soluble salts $M_2X$,$MX$,and $MX_3$ are identical. What will be the order of their solubilities $(s)$?

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