The reaction $CH _{3} COF + H _{2} O \quad \rightleftharpoons CH _{3} COOH + HF$
Condition $I$ $:$ $\left[ H _{2} O \right]_{0}=1.00 \,M$
$\left[ CH _{3} COF \right]_{0}=0.01 \,M$
Condition $II$ $:$ $\left[ H _{2} O \right]_{0}=0.02 \,M$
$\left[ CH _{3} COF \right]_{0}=0.80 \,M$
Condition - $I$
Condition - $II$
Time
$(t)$
$min$
$\left[ CH _{3} COF \right]$ $M$
Time
$(t)$
$min$
$\left[ H _{2} O \right] \,M$
$0$
$0.01000$
$0$
$0.0200$
$10$
$0.00867$
$10$
$0.0176$
$20$
$0.00735$
$20$
$0.0156$
$40$
$0.00540$
$40$
$0.0122$
Determine the order of reaction and calculate rate constant.
The reaction $CH _{3} COF + H _{2} O \quad \rightleftharpoons CH _{3} COOH + HF$
Condition $I$ $:$ $\left[ H _{2} O \right]_{0}=1.00 \,M$
$\left[ CH _{3} COF \right]_{0}=0.01 \,M$
Condition $II$ $:$ $\left[ H _{2} O \right]_{0}=0.02 \,M$
$\left[ CH _{3} COF \right]_{0}=0.80 \,M$
| Condition - $I$ | Condition - $II$ | ||
|
Time $min$ |
$\left[ CH _{3} COF \right]$ $M$ |
Time $min$ |
$\left[ H _{2} O \right] \,M$ |
| $0$ | $0.01000$ | $0$ | $0.0200$ |
| $10$ | $0.00867$ | $10$ | $0.0176$ |
| $20$ | $0.00735$ | $20$ | $0.0156$ |
| $40$ | $0.00540$ | $40$ | $0.0122$ |
Determine the order of reaction and calculate rate constant.
$(i)$ Reaction is pseudo $1^{\text {st }}$ reaction, in which $\left[\mathrm{H}_{2} \mathrm{O}\right]$ is constant.
$(ii)$ Reaction is pseudo $1^{\text {st }}$ reaction, but in order to this reaction $=2$.
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The experimental data for reaction
$2A + B_2 \longrightarrow 2AB$
Exp.
$[A]$
$[B_2]$
Rate $(mol\,L^{-1}\,S^{-1})$
$1$
$0.50$
$0.50$
$1.6 \times {10^{ - 4}}$
$2$
$0.50$
$1.00$
$3.2 \times {10^{ - 4}}$
$3$
$1.00$
$1.00$
$3.2 \times {10^{ - 4}}$
The rate law
The experimental data for reaction
$2A + B_2 \longrightarrow 2AB$
| Exp. | $[A]$ | $[B_2]$ | Rate $(mol\,L^{-1}\,S^{-1})$ |
| $1$ | $0.50$ | $0.50$ | $1.6 \times {10^{ - 4}}$ |
| $2$ | $0.50$ | $1.00$ | $3.2 \times {10^{ - 4}}$ |
| $3$ | $1.00$ | $1.00$ | $3.2 \times {10^{ - 4}}$ |
The rate law