The radial probability distribution curve for an orbital comprises of $3$ maxima. If the orbital has $3$ angular nodes as well,then the orbital can be:

Five valence electrons of $P^{15}$ are labelled as $\boxed{AB}_{3s} \,\boxed{X|Y|Z}_{3p}$. If the spin quantum numbers of $B$ and $Z$ are $+\frac{1}{2}$,the group of electrons with three of the quantum numbers $(n, l, m)$ the same are:

The number of orbitals in the fourth principal quantum number $(n = 4)$ is:

Identify the neutral atoms having the outermost electronic configurations as $2p^4$,$3s^2$,and $2p^3$ respectively.

Identify the incorrect statement from the following.

The number of unpaired electrons in $1s^2 2s^2 2p^3$ is: