The product formed in the reaction is:

  • A
    $4-$hydroxycyclohexanecarboxylic acid methyl ester
  • B
    $4-$hydroxycyclohexylmethanol
  • C
    $4-$oxocyclohexylmethanol
  • D
    cyclohex$-3-$enecarboxylic acid methyl ester

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$A$ mixture of benzaldehyde and formaldehyde on heating with aqueous $NaOH$ solution gives :-

$A$ tertiary alcohol $H$ upon acid-catalysed dehydration gives a product $I$. Ozonolysis of $I$ leads to compounds $J$ and $K$. Compound $J$ upon reaction with $KOH$ gives benzyl alcohol and a compound $L$,whereas $K$ on reaction with $KOH$ gives only $M$.
$1.$ Compound $H$ is formed by the reaction of
$2.$ The structure of compound $I$ is
$3.$ The structures of compounds $J, K$ and $L$,respectively,are
$(A)$ $PhCOCH_3, PhCH_2 COCH_3$ and $PhCH_2 COO^{-} K^{+}$
$(B)$ $PhCHO, PhCH_2 CHO$ and $PhCOO^{-} K^{+}$
$(C)$ $PhCOCH_3, PhCH_2 CHO$ and $CH_3 COO^{-} K^{+}$
$(D)$ $PhCHO, PhCOCH_3$ and $PhCOO^{-} K^{+}$
Give the answer for questions $1, 2$ and $3.$

The product $(A)$ is:

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Among the following,the compounds which can be reduced with formaldehyde and conc. $aq.$ $KOH$ are $.....$

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