The principal that amounts to ₹ 4913 in 3 yea | vedclass

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Question

Let the principal be $P$.

$	herefore$

$P\left(1+\frac{6 \frac{1}{4}}{100}ight)^{3}=4913$

or $P\left(1+\frac{25}{400}ight)^{3}=4913$

o

Vedclass · Accepted Answer

$4096$

Vedclass · Answer

Let the principal be $P$.

$	herefore$

$P\left(1+\frac{6 \frac{1}{4}}{100}ight)^{3}=4913$

or $P\left(1+\frac{25}{400}ight)^{3}=4913$

or

$P=\frac{4913}{\left(1+\frac{1}{16}ight)^{3}}=\frac{4913 	imes 16^{3}}{17^{3}}=₹ 4096$

The principal that amounts to ₹ $4913$ in $3$ years at $6 \frac{1}{4} \%$ per annum compound interest compounded annually (In ₹) is.

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