(C) Let the $3$ different amino acids be $A, B,$ and $C$. Since each amino acid is used exactly once,the number of possible tripeptides is equivalent

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(C) Let the $3$ different amino acids be $A, B,$ and $C$. Since each amino acid is used exactly once,the number of possible tripeptides is equivalent to the number of permutations of $3$ distinct items taken $3$ at a time. This is calculated as $3! = 3 \times 2 \times 1 = 6$. The possible combinations are: $ABC, ACB, BAC, BCA, CAB, CBA$.