The number of terms in the finite A.P. 13, 26 | vedclass

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(C) The given sequence is an arithmetic progression $(A.P.)$ where the first term $a = 13$.The common difference $d = 26 - 13 = 13$.The last term $T_n

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(C) The given sequence is an arithmetic progression $(A.P.)$ where the first term $a = 13$.The common difference $d = 26 - 13 = 13$.The last term $T_n = 650$.The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.Substituting the values: $650 = 13 + (n - 1)13$.Dividing the entire equation by $13$: $50 = 1 + (n - 1)$.$50 = n$,so $n = 50$.Therefore,the number of terms in the $A.P.$ is $50$.

The number of terms in the finite $A.P.$ $13, 26, 39, \ldots, 650$ is ........

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