The molar conductivity is maximum for the solution of concentration $...........$ $M$.

Conductivity of a saturated solution of a sparingly soluble salt $AB$ at $298 \ K$ is $1.85 \times 10^{-5} \ S \ m^{-1}$. Solubility product of the salt $AB$ at $298 \ K$ is. Given $\Lambda_{m}^{\circ}(AB) = 140 \times 10^{-4} \ S \ m^{2} \ mol^{-1}$.

The factor which is not affecting the conductivity of any solution is

Calculate the molar conductivity of $NH_4OH$ at infinite dilution if the molar conductivities of $Ba(OH)_2$,$BaCl_2$,and $NH_4Cl$ at infinite dilution are $520$,$280$,and $129 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.

Molar conductivity of $0.01 \ M$ $HCl$ solution is $400.0 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$. Calculate the conductivity of $HCl$ solution.

If $0.01 \, M$ solution of an electrolyte has a resistance of $40 \, \Omega$ in a cell having a cell constant of $0.4 \, cm^{-1}$,then its molar conductance in $ohm^{-1} \, cm^2 \, mol^{-1}$ will be :-