The mean values for the radial distance for d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the formation of $PF_5$,phosphorus undergoes $sp^3d$ hybridization. During hybridization,the orbitals involved ($3s$,$3p$,and $3d$) undergo mix

Vedclass · Accepted Answer

$0.40 \ \mathring{A}$,$0.48 \ \mathring{A}$,$0.85 \ \mathring{A}$

Vedclass · Answer

(B) In the formation of $PF_5$,phosphorus undergoes $sp^3d$ hybridization. During hybridization,the orbitals involved ($3s$,$3p$,and $3d$) undergo mixing to form five equivalent $sp^3d$ hybrid orbitals. The $3d$ orbital,which is initially very diffuse (large radial distance of $2.4 \ \mathring{A}$),contracts significantly to participate in bonding with the electronegative fluorine atoms. The $3s$ and $3p$ orbitals remain relatively unchanged in their radial distribution compared to the $3d$ orbital. Therefore,the radial distances become approximately $0.40 \ \mathring{A}$,$0.48 \ \mathring{A}$,and $0.85 \ \mathring{A}$ respectively,reflecting the contraction of the $3d$ orbital.

Similar Questions

In which of the following pairs,both the species have the same hybridisation?
$I$. $SF_4, XeF_4$
$II$. $I_3^-, XeF_2$
$III$. $ICl_4^+, SiCl_4$
$IV$. $ClO_3^-, PO_4^{3-}$

Which of the following overlapping is not present in $XeO_3$ molecule?

The type of hybrid orbitals used by the chlorine atom in $ClO_2^-$ is

With which of the given pairs does $CO_2$ resemble in terms of structure?

What is the hybridization of sulfur in $SO_2$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module