The major products of the following reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction proceeds in two main steps:$1$. Reimer-Tiemann reaction: $4$-chlorophenol reacts with $CHCl_3$ and aqueous $NaOH$ to form $5$-chloro$

Vedclass · Accepted Answer

$2-$hydroxy$-5-$chlorobenzyl alcohol and formic acid

Vedclass · Answer

(B) The reaction proceeds in two main steps:$1$. Reimer-Tiemann reaction: $4$-chlorophenol reacts with $CHCl_3$ and aqueous $NaOH$ to form $5$-chloro$-2-$hydroxybenzaldehyde.$2$. Cannizzaro reaction: The aldehyde formed reacts with $HCHO$ and concentrated $NaOH$ (cross-Cannizzaro reaction). The aldehyde is reduced to the corresponding alcohol ($5$-chloro$-2-$hydroxybenzyl alcohol),and $HCHO$ is oxidized to sodium formate $(HCOONa)$.$3$. Acidification: Finally,treatment with $H_3O^+$ converts the phenoxide and formate salt into $5$-chloro$-2-$hydroxybenzyl alcohol and formic acid $(HCOOH)$.

The major products of the following reaction are:

Similar Questions

The compound that is most difficult to protonate is

The correct order of boiling point for the given compounds is:

The major product of the following reaction sequence is:
$C_6H_5OH \xrightarrow[(ii) NaOH, (iii) H^+]{(i) CHCl_3, NaOH(aq)} ?$

Which group is present in phenol? What is the effect of this group on the ring and its reactions?

Which statement is true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module