The height at which the weight of the body become $\frac{1}{9}^{th}$. Its weight on the surface of earth (radius of earth $R$)
The height at which the weight of the body become $\frac{1}{9}^{th}$. Its weight on the surface of earth (radius of earth $R$)
- A
$h = 3R$
- B
$h = R$
- C
$h = \frac{R}{2}$
- D
$h = 2R$
Similar Questions
If both the mass and the radius of the earth decrease by $1\%$ , the value of the acceleration due to gravity will
If both the mass and the radius of the earth decrease by $1\%$ , the value of the acceleration due to gravity will
Assuming the earth to be a sphere of uniform mass density, how much would a body weigh (in $N$) half way down to the centre of the earth if it weighed $250\; N$ on the surface?
Assuming the earth to be a sphere of uniform mass density, how much would a body weigh (in $N$) half way down to the centre of the earth if it weighed $250\; N$ on the surface?
If a tunnel is cut at any orientation through earth, then a ball released from one end will reach the other end in time ........ $\min$ (neglect earth rotation)
If a tunnel is cut at any orientation through earth, then a ball released from one end will reach the other end in time ........ $\min$ (neglect earth rotation)
$Assertion$ : Space rocket are usually launched in the equatorial line from west to east
$Reason$ : The acceleration due to gravity is minimum at the equator.
$Assertion$ : Space rocket are usually launched in the equatorial line from west to east
$Reason$ : The acceleration due to gravity is minimum at the equator.
- [AIIMS 2017]
A body weighs $72 N$ on surface of the earth. When it is taken to a height of $h=2 R$, where $R$ is radius of earth, it would weigh ........ $N$
A body weighs $72 N$ on surface of the earth. When it is taken to a height of $h=2 R$, where $R$ is radius of earth, it would weigh ........ $N$