The figure shows a velocity-time graph of a particle moving along a straight line The total distance travelled by the particle is ........ $m$
$66.6$
$51.6 $
$0$
$36.6$
$x-t$ graph for a uniformly accelerated particle is as shown in the figure. Then find the average velocity between points $(i)$ and $(ii)$ ......... $ms^{-1}$
A car travels $6\, km$ towards north at an angle of $45^o$ to the east and then travels distance of $4\, km$ towards north at an angle $135^o$ to east. How far is the point from the starting point? What angle does the straight line joining its initial and final position makes with the east?
What do you mean by projectile motion and projectile particle ? Find the value of the position of a projectile particle at any instant of time.
A point moves in $x-y$ plane as per $x=kt,$ $y = kt\left( {1 - \alpha t} \right)$ where $k\,\& \,\alpha \,$ are $+ve$ constants. The equation of trajectory is
The figure shows the velocity and the acceleration of a point like body at the initial moment of its motion. The direction and the absolute value of the acceleration remain constant. Find the time when the speed becomes minimum.........$s$ (Given : $a = 4\, m/s^2, v_0 = 40\, m/s, \phi =143^o$)