The electric flux passing through the cube for the given arrangement of charges placed at the corners of the cube (as shown in the figure) is
The electric flux passing through the cube for the given arrangement of charges placed at the corners of the cube (as shown in the figure) is
- A
$\phi = \frac{1}{{2{ \in _0}}}$
- B
$\phi = \frac{{ - 1}}{{2{ \in _0}}}$
- C
$\phi = \frac{{ - 1}}{{{ \in _0}}}$
- D
$\phi = \frac{1}{{{ \in _0}}}$
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Why do electric field lines not form closed loop ?
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A disk of radius $a / 4$ having a uniformly distributed charge $6 \mathrm{C}$ is placed in the $x-y$ plane with its centre at $(-a / 2,0,0)$. A rod of length $a$ carrying a uniformly distributed charge $8 \mathrm{C}$ is placed on the $x$-axis from $x=a / 4$ to $x=5 a / 4$. Two point charges $-7 \mathrm{C}$ and $3 \mathrm{C}$ are placed at $(a / 4,-a / 4,0)$ and $(-3 a / 4,3 a / 4,0)$, respectively. Consider a cubical surface formed by six surfaces $x= \pm a / 2, y= \pm a / 2$, $z= \pm a / 2$. The electric flux through this cubical surface is
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- [IIT 2009]
A point charge $q$ is placed at a distance $a/2$ directly above the centre of a square of side $a$. The electric flux through the square is
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When the electric flux associated with closed surface becomes positive, zero or negative ?
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Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is $8.0 \times 10^{3} \;Nm ^{2} / C .$
$(a)$ What is the net charge inside the box?
$(b)$ If the net outward flux through the surface of the box were zero, could you conclude that there were no charges inside the box? Why or Why not?
Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is $8.0 \times 10^{3} \;Nm ^{2} / C .$
$(a)$ What is the net charge inside the box?
$(b)$ If the net outward flux through the surface of the box were zero, could you conclude that there were no charges inside the box? Why or Why not?