The diagram below shows an object placed at a | vedclass

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(C) Initially,the object is at $2f$,so the image is formed at $2f$ on the other side (at point $S$).$(i)$ When a parallel-sided glass block is inserte

Vedclass · Accepted Answer

Further away from $S$ (Glass block); Further away from $S$ (Converging lens)

Vedclass · Answer

(C) Initially,the object is at $2f$,so the image is formed at $2f$ on the other side (at point $S$).$(i)$ When a parallel-sided glass block is inserted,the light rays shift laterally but remain parallel to their original path. This causes the virtual object for the convex lens to appear closer to the lens. Since the object distance $u$ effectively decreases $(u  2f)$. Thus,the image shifts further away from $S$.(ii) When a converging lens of long focal length is inserted,it makes the rays more convergent before they hit the convex lens. This effectively makes the object appear closer to the convex lens. Consequently,the image distance $v$ increases $(v > 2f)$,shifting the image further away from $S$.

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