The current gain $\beta$ of a transistor is $50$. The input resistance of the transistor when used in the common emitter mode is $1\,k\Omega$. The peak value of the collector current for an input peak voltage of $0.01\,V$ is ...... $\mu A$.

$A$ transistor connected in common emitter mode has a load resistance of $5 \, k\Omega$. If the input peak voltage is $5 \, mV$ and the current gain $(\beta)$ is $50$, find the voltage gain.

The region in the output voltage versus input voltage graph where a transistor can be used as an amplifier is

For a constant collector-emitter voltage of $8\,V$,the collector current of a transistor changed from $4\,mA$ to $6\,mA$,whereas the base current changed from $20\,\mu A$ to $25\,\mu A$. If the transistor is in the active state,the small signal current gain (current amplification factor) will be:

In a common emitter $(CE)$ amplifier having a voltage gain $G$,the transistor used has a transconductance of $0.03\,mho$ and a current gain of $25$. If the above transistor is replaced with another one with a transconductance of $0.02\,mho$ and a current gain of $20$,the new voltage gain will be:

In $n-p-n$ transistor,in $CE$ configuration: